Respuesta :

[tex]\bf \textit{surface area of a cylinder}\\\\ s=2\pi r(h+r)\quad \begin{cases} r=radius\\ h=height\\ ------\\ h=11\\ r=9 \end{cases}\implies s=2\pi (9)(11+9) \\\\\\ s=18\pi (20)\implies s=360\pi [/tex]