In these questions, we have equivalent ratios given and we have to find the missing number .
For the first one, we have
[tex] \frac{21}{7}= \frac{x}{1} [/tex]
Here the missing number is represented by x .
Dividing both 21 and 7 by 7,
[tex] \frac{3}{1} = \frac{x}{1} [/tex]
That gives, x=3
For the second question, we have
[tex] \frac{72}{12} = \frac{x}{1} [/tex]
Dividing both 72 and 12 by 12, we will get
[tex] \frac{6}{1} = \frac{x}{1} [/tex]
That gives x=6
