jakescameron23p4qs5a jakescameron23p4qs5a

26-02-2018
Mathematics

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Evaluate12P3 and10C4

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estherng0722 estherng0722

26-02-2018

[tex] 12P3 = \frac{12!}{(12-3)!} [/tex]
=1320
[tex]10C4 = \frac{10!}{4!(10-4)!} [/tex]
= 210

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