mcgraw1013
mcgraw1013 mcgraw1013
  • 26-03-2018
  • Mathematics
contestada

Solve for z. 3z + 1 = 4z + 19 z =

Respuesta :

hackermcpe
hackermcpe hackermcpe
  • 26-03-2018
3z + 1 = 4z + 19

Subtract 4z from each side
3z + 1 − 4z = 4z + 19 − 4z
−z + 1 = 19

Subtract 1 from each side
−z + 1 − 1 = 19 − 1
−z = 18

Divide each side by -1
-z ÷ -1 = 18 ÷ -1
z = -18
Answer Link
TobeySnaps
TobeySnaps TobeySnaps
  • 27-11-2018

Answer:

-z ÷ -1 = 18 ÷ -1

z = -18


Answer Link

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