f(x)=2x^2-8x+8 This is a quadratic equation, and its graph is a vertical parabola f(x)=ax^2+bx+c a=2>0 (positive), then the parabola opens upward b=-8 c=8
The Vertex is the minimum point of the parabola: V=(h,k) The abscissa of the Vertex is: h=-b/(2a)=-(-8)/[2(2)]=8/4→h=2
The axis of symmetry is the vertical line: x=h→x=2
Answer: The axis of symmetry for f(x) = 2x^2 − 8x + 8 is x=2
