how many moles of CaCl2 are required to prepare 2.00 liters of 0.700 M CaCl2

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24-04-2018
Chemistry

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how many moles of CaCl2 are required to prepare 2.00 liters of 0.700 M CaCl2

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transitionstate transitionstate · Answer 1 · 2018-05-03T02:46:53+02:00

As we know,

Molarity = Moles / Vol. of Solution ------- (1)

Data Given:
Molarity = 0.70 mol.L⁻¹

Volume = 2.00 L
To Find:
Moles = ?

Solution:
Solve eq. 1 for Moles,

Moles = Molarity × Volume
Putting Values,
Moles = 0.70 mol.L⁻¹ × 2.00 L

Moles = 1.4 mol