An ideal gas in a sealed container has an initial volume of 2.55 l. at constant pressure, it is cooled to 18.00 °c where its final volume is 1.75 l. what was the initial temperature?
Solution: Let suppose the Gas is acting Ideally, Then According to Charle's Law, P₁ / T₁ = P₂ / T₂ Solving for T₁, T₁ = V₁ × T₂ / V₂ Putting Values, T₁ = (2.55 L × 291.15 K) ÷ 1.75 L