A Target consists of two concentric similar octagons. The outside octagon has a side length of 2 feet and an area of 19.28 square feet. If the inside octagon has a side length of 1.5 feet, what is the area of the inside octagon?

Respuesta :

Rodiak
General formula for regular polygon is:
[tex]A= \frac{1}{4} *n* a^{2} *cot( \frac{180}{n} )[/tex]

For the inside octagon we have:
[tex]A= \frac{1}{4} *8* 1.5^{2} *cot( \frac{180}{8} )[/tex]
[tex]A=10.86 ft^{2} [/tex]